if there are more than 5 things, to the other guys, but is this the optimal strategy?)Ĭhances to solve an encounter in 3 turns with optimal strategy: in the first turn? If yes, how to proceed? (I would offer the things which turned "yellow" in a different order in the 2nd turn, and if there is space remaining, offer things #6 etc. When there are 3 things to offer, I assume that I will succeed, when I do the following:Ģnd turn: offer thing #2 to everyone who is still thereģrd turn: offer thing #3 to the remaining people.īut what is the optimal strategy when there are more than 3 things to offer? Offer thing #1 to person #1, thing #2 to person #2, etc. * Swiss Lotto " 6 aus 42 plus 1 aus 6": ~1 in 31 millions * German "Lotto 6 aus 49": ~1 in 139.8 millions * Austrian "Lotto 6 aus 45": ~1 in 8 millions I would be interested in the true number of things to offer in each encounter, so that I could calculate the true chance) Did anyone take notes, how many things can be selected to offer in each turn of difficulty levels 1, 2 and 3? (Based on these numbers, and assuming 7 things for each encounter ("typical negotiation in the middle of difficulty III" according to the announcement), the chance to solve every of the 16 encounters of difficulty 3 in 3 turns would be 0.326^16 = 1 in 61.4 million, which is in the same order of magnitude as the chance for winning the lottery*).
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |